#9 review
Could somone go over the simplification of the numerator on this one, I was confused as to how it ended up being what the answer said it was. Thanks
posted by moperson at 10:24 PM
Blog for students in Mr. Karafiol's Period 4 Precalculus BC class to talk about math, learning math, etc.
posted by moperson at 10:24 PM
1 Comments:
basically the way i solved it was that i broke the numerator into two fractions over h; sqrt(2x+2h+1)/h - sqrt(2x+1)/h; then you can simply multiply each fraction by the numerator over itself [i.e. sqrt(2x+2h+1)/h * sqrt(2x+2h+1)/sqrt(2x+2h+1), and the same for the other part of the expression]. After you do that you should end up with:
((2x+2h+1)-(2x+1))/ (h*sqrt(2x+2h+1)- h*sqrt(2x+1)), which reduces to (2/(sqrt(2x+2h+1)- sqrt(2x+1))
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