#6 on final review sheet
I'm having trouble with number 6 on the review sheet. I tried taking the zeroes and dividing P(x) by the terms (x-r1)*(x-r2) to get a remainder but it got messy. Any other suggestions on how to do this problem?
posted by Carrie Desmond at 12:47 PM
1 Comments:
Since 2+5i is a root, 2-5i should also be a root. plus, x=-4 is also a root, so the function can be written as P(x)=(x-2+5i)*
(x-2-5i)*(x+4). expand the answer, i got P(x)=x^3+13x+116. the coefficient of x^2 is 0, so b=0, which is c.
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