homework
I dont understand how to do number 64 in 6.3 and #28 in 6.4. thanks!
melissa
melissa
posted by melishappy at 4:09 PM
Sunday, January 28, 2007
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- HW #39 Section 6.3
- Even v. Odd Functions
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3 Comments:
6.3.64
You should have a general idea of how the graphs look by now. If not you can graph the functions to see whether they are even or odd. refer back to previous notes for even and odd functions.
6.4.28
sin(t)=k where k=(-1,1)
The question is asking for what values of t would k be in the interval (-1,1). For the values k=(-1,1), t=(3pi/2, pi/2)
a even function is when you replace x by -x, and get the same values. A odd function is when you replace x and y with -x and -y, and get the same function. Just note that and you should be able to do it. Also use identities, such as, a. f(t) = sin t, if t->-t and f(t) -> -f(t), it will be -f(t) = sin (-t), sin(-t)=-sin(t), so -f(t) = -sin(t), which is the same as f(t) = sin(t)
so its odd
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