Am i overthinking #19, or is the answer simply (a+b)? If tan(x) = sin(x)/cos(x) and tan here is (a+b)/(a-b), can i just assume that sin is (a+b) and cos is (a-b)?
Also, I agree with Sam about 17b and with Carrie about 25.
Also, I agree with Sam about 17b and with Carrie about 25.
posted by Casey Blue at 10:01 PM
2 Comments:
mmmyeah, i just realized that for 19, sin could only equal (a+b) if the radius was one (if this was all on the unit circle). and i'm not sure that's the case.
so how do you do this?
Sin(t)=a+b because tan(t)=sin(t)/cos(t) so sin(t)=a+b. Even if we are not on the unit circle, the tangent (slope) would be the same because it is merely a ratio between the sine and the cosine. For example if the radius was 7, tan(t)=(7(a+b))/(7(a-b)).
Post a Comment
<< Home