section 8.5 #59
How would u do the proof for arcsin(-x)=-arcsin(x) ? I don't understand how the chunking method would work for this problem either.
posted by Elena at 10:42 PM
Blog for students in Mr. Karafiol's Period 4 Precalculus BC class to talk about math, learning math, etc.
posted by Elena at 10:42 PM
3 Comments:
ok, here's what I'd do. Sin(asin(-x))=-x, right? Also, Sin(-asin(x))=-sin(asin(x)), since sin(-x)=-sin(x), so sin(-asin(x))=-sin(asin(x))=-x as well.
Will Mr. Karafiol please be kind and reinvite me? My email is a.blue.wave.of.bass@gmail.com
I just realized I didn't answer your question. My fault. OK, if y=sin(-x), then y=-sin(x), or, better yet, -y=sin(x). Therefore, x=arcsin(-y) and -x=arcsin(y), aka: x=-arcsin(y), if you apply arcsine to each side of each equation. Then by some property of equality (my first instinct is transitive, but there's something telling me that's wrong) arcsin(-x)=-arcsin(x).
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