Solution to 7.2 #34
This is the diagram for #34.
a. Since angle DAC=55 degrees and angle DAB=70 degrees, angle CAB=70-55=15 degrees. CB^2=AC^2+AB^2-2*AC*AB*cos(15)=180^2+400^2-2*180*400*cos(15), CB=230.88
b. Measure angle ACB. 400^2=180^2+230.88^2-2*180*230.88*cos(angle ACB), angle ACB=153.36degrees. The angle of turn = 180-153.36= 26.64degrees.
posted by Yuchen Z. at 1:56 PM
6 Comments:
out of curiosity...how did you make that graph?
This comment has been removed by the author.
isn't ac 180?
that will make cb 230.9
To manny:
oops...my fault.
To monica:
I used paint...:)
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