Blog for students in Mr. Karafiol's Period 4 Precalculus BC class to talk about math, learning math, etc.
posted by Donovan at 5:35 PM
The first thing i did for this problem was to factor the second equation. I saw that the x term was replaced with a (x-2) so i factor a (x-2) out of the numerator. So g(x) would be 3[-2(x-2)]/(x-2)^2+10. Then you can interpret it from there.
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The first thing i did for this problem was to factor the second equation. I saw that the x term was replaced with a (x-2) so i factor a (x-2) out of the numerator. So g(x) would be 3[-2(x-2)]/(x-2)^2+10. Then you can interpret it from there.
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