# 2 on review and log properties

I was going over perhaps a nice way of remembering how to find logs with the table for those of us who would rather use numbers (first and foremost, this is an easier way for me to think about it). When there is a log of a number like 2.9, and we are asked to give the log of 290, think of 290 as 2.9*10^2, becuase the answer is the log of 2.9 plus that number 2. It works for negative powers too, in which case you would subtract. Then, when you are given a nicer log like the log of 3 and the problem asks for the log of 27, you would think of log 27 as log 3^3 and take the initial value for log 3 and multiply by the power, 3. Again, it works for negative powers too. Here's the example
log 3 = .477
log 27 = log 3^3 = 3 log 3 = .477*3 = 1.43
log 1/27 - log 3^-3 = .477*-3 = -1.43