#21
#21
f(x)=log(2x-1) and to do the reverse f(x) changes to y so then y=log(2x-1). then switch x and y=>x=log(2y-1) and solve for y which is y=(10^x+1)/2 or f^-1(x)=(10^x+1)/2 and it is B.
Melissa
f(x)=log(2x-1) and to do the reverse f(x) changes to y so then y=log(2x-1). then switch x and y=>x=log(2y-1) and solve for y which is y=(10^x+1)/2 or f^-1(x)=(10^x+1)/2 and it is B.
Melissa
posted by melishappy at 5:46 PM
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