SAT-II #46
Question 46 is the rediculous logarithm problem, that I found very hard to concentrate on and sort of annoying. I got (c) for the answer but it was half guess and half math because I couldn't get the expression they gave to simplify to the same sort of answers they were giving. Did anyone successfully do this problem?
posted by Anonymous at 11:15 AM
1 Comments:
I said a. Logb(2)+logb(B)=logb(2B)
1/2logb(y)-1/2logb(w)=1/2logb(y/w)
logb(2B)+1/2logb(y/w)=1/2logb(2By/w).
Only thing i'm not sure on is the 1/2. However, when you add to logs with the same base you multiply the values in parenthesis. When you you subtract two logs of the same base you divide whats in parenthesis. All the logs in this problem have the same base so if you applyt hese rulesi think you end up with a.
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