Thursday, May 10, 2007

10-Review #49

I'm having trouble remembering how to do this one. It asks how to rotate the x-y axes to eliminate xy from x^2+xy+y^2-3y-6=0. Any help?

3 Comments:

Blogger Dylan Gschwind said...

well in order to get rid of the xy in the equation
Ax^2+Bxy+Cy^2+Dx+Ey+F=0 You have to rotate theaxes therough an angle of theta, where cot(2*theta)=(A-C)/B

11:58 AM  
Blogger Yuchen Z. said...

Do we need to know the formula cot(2*theta)=(A-C)/B ? Did we cover 10.3A about rotation?

4:32 PM  
Blogger battlejoe18 said...

Actually, we did not cover this to the best of my knowledge, and I too wonder if we need this. but, we probably do. I don't conceptually understand this, though.

11:22 PM  

Post a Comment

<< Home