Group Work on Functions
I am confused on problem #7 on the "Group Work on Functions" sheet. Someone told me the function Df(x)=x^2+xh+h has already simplified, and we just need to substitute in numbers, we don't need to use (f(b)-f(a))/b-a to find the ARC (and the IRC). Is that correct? and how to do this problem?
posted by Yuchen Z. at 2:11 PM
5 Comments:
i wasn't sure about that either. i tried substituting and it seemed to be right.
oops. i meant i used the ARC formula, NOT substitution.
I thought that Df(x) was the simplified difference quotient so all you had to do was substitute for x and h depending on what interval you want to compute for.
I think George is right, although I am a little confused as to how Df(x) = (f(x+h) - f(x))/h simplifies to Df(x) = x^2+hx+h.
I just assumed that we were supposed to pretend this was the difference quotient and substitute in the x and h values accordingly.
But since the values for h in the intervals [6, 6.1] and [6, 6.01] are .1 and .01 accordingly, and these are the values for ARC, how small of an h should we pick for the IRC? .000001??
Keep using smaller and smaller h's until the ARC values don't change much anymore (but seem to settle down at some number)
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