Blog for students in Mr. Karafiol's Period 4 Precalculus BC class to talk about math, learning math, etc.
posted by moperson at 7:14 PM
yeah...im confused about how to find the answer to number eight too
for number 12, to find h(x) you just subtract find f(x)-g(x). So you get h(x)=(1/(x^2-x))-(1/x)=(-x^2/(x^3-x^2) and to simplify that you just divide by x^2 which gives you (-1/(x-1))
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2 Comments:
yeah...im confused about how to find the answer to number eight too
for number 12, to find h(x) you just subtract find f(x)-g(x). So you get h(x)=(1/(x^2-x))-(1/x)=(-x^2/(x^3-x^2) and to simplify that you just divide by x^2 which gives you (-1/(x-1))
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