Solving parallelograms w/ diagonals
i am having problems figuring this out. i am aware that the magic formula is 1/2*ab*sin C, but how do i get this when, for instance, the diagonlas are given as 18 and 24, with angle 30 deg. like on the groupwork. i heard the answer was 108. how does this make sense?
posted by battlejoe18 at 4:21 PM
3 Comments:
diagonals of a parallelogram bisects each other, and the bisect each other a 30 degrees, since they bisect each other, the sides a and b will be 18/2 and 24/2, C will be 30, so you can find two triangles' area using the formula 1/2absinC, then 180-C to find the other angle, then use the formula again then add it. Hope this helps
When it says "bisects at 30 degrees", exactly what angle in 30 degrees?
The angle which is 30 degrees is the smaller of the angles which opens from the two diagonals where they intersect. From this you also know that the bigger angle is 150.
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