Projection and Parallel
I'm having trouble doing the problems on projection and don't understand the book's explanation. Can someone explain how to do this? Also, the parallel ones aren't working out for me either. Thanks
posted by Carrie Desmond at 3:24 PM
2 Comments:
I don't have time to fully explain this, however if you look at the formula in the book, it should give you two answers, because you plug in both coordinates for the vector.
For the parallel problems, you just need to calculator the slope of each vector in question. If the two vectors have the same slope, they are parallel.
The projection problems can be solved by using the formula proj(subu)v=[(u*v)/(magnitudeofu*magnitudeofv)]*v. Since this calculation yields a vector (not a scalar), this is basically giving you the vector of the shadow u casts on to v. However, I don't think I'd do a good job explaining where the formula comes from (I'm a little confused about this too). There is a proof on page 597 if you want a more thorough explanation.
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