Semester Review Packet # 54
I know we've done multiple problems like this one but could someone please remind me how to do it?
sin a = 4/5 and sin b = 5/13
find sin (a-b)
sin a = 4/5 and sin b = 5/13
find sin (a-b)
posted by brianhorwich at 11:51 AM
1 Comments:
If you recall that the subtraction identity for sine is sin ( A - B ) = sin A cos B - cos A sin B, then you can just convert the sines into cosines that you need, and plug everything back in and solve.
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