How Do I solve Problems Like problems 2.3:31 Correctly
I have been having a little trouble with some of problems like 31 from 2.3. I am not sure what is the best way to determine the equation that is to be graphed. How do I form an equation that will encorporate the prices and the possible dimensions? If anyone can help, it would be greatly appreciated.
posted by shaun at 3:35 PM
1 Comments:
What I did was following.
width=x, length=2x, height=y.
volume=base*height
38.72=x*2x*y
y=19.36/x^2
cost=12*base+8*side
538.56=(12*width*length)+(8*2*length*height)+(8*2*width*height)
538.56=12*(2x*x)+8*2*2x*(19.36/x^2)+8*2*x*(19.36/x^2)
x=2.2 or x=3.23
height must be at least 3ft.
if x=3.23, then height<3, so x=2.2
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