How to solve number 11a on the pretest
Here is what i did to solve this problem:
First make z = a + bi and w = c + di.
Second, use the distance formula using these two points to get sqrt((a-c)^2+((b-d)*i)^2)
This is the true distance between the points.
Now, do abs(z-w). What this means is the distance from the origin after subtracting these two points. After subtracting them you get a+bi-c-di, or (a-c)+(b-d)i. Simply use the distance formula here to find the distance from zero to get the equation sqrt((a-c)^2+((b-d)*i)^2), which is identical to the equation found when using the distance formula of the two points directly.
I hope that helped... if not ask me to clarify please.
First make z = a + bi and w = c + di.
Second, use the distance formula using these two points to get sqrt((a-c)^2+((b-d)*i)^2)
This is the true distance between the points.
Now, do abs(z-w). What this means is the distance from the origin after subtracting these two points. After subtracting them you get a+bi-c-di, or (a-c)+(b-d)i. Simply use the distance formula here to find the distance from zero to get the equation sqrt((a-c)^2+((b-d)*i)^2), which is identical to the equation found when using the distance formula of the two points directly.
I hope that helped... if not ask me to clarify please.
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