pretest number 4 and 13
4:
i got confused when i looked at the sign graph for number 4,
for A i thought that the degree was even because when the negative were plugged in they became positive, but i didnt understand why 04 was negative, if the degree were even wouldn't they all be even.
and for b i thought that the leading coeff was neg because if you raised a negative # by an odd degree ud get a neg. number and if you multiply a negative number by a negative number you'd get a positive number.
can someone please clarify how i should look at 4 a and b
13:
how do you start 13?
sarah iqbal
i got confused when i looked at the sign graph for number 4,
for A i thought that the degree was even because when the negative were plugged in they became positive, but i didnt understand why 0
and for b i thought that the leading coeff was neg because if you raised a negative # by an odd degree ud get a neg. number and if you multiply a negative number by a negative number you'd get a positive number.
can someone please clarify how i should look at 4 a and b
13:
how do you start 13?
sarah iqbal
posted by Anonymous at 9:30 PM
1 Comments:
The first thing i did was to sketch a picture of the graph and to list the roots. Looking at the sign graph we see that at -3 the sign doesnt change that would indicate that the factor (x+3) was raised to an even power. The factors were (x-4)(x-1)(x)(x+3)^even power. We see that the function is of an odd degree because a odd+even=odd degree.
For part b, just plug in a value greater than than the end factors of the function. For example i chose 100 and when plugeed in, the interval [4,infinity] is positve, but the sign graph shows a negative value. So the leading coefficient would have to be negative.
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