Supplement #3
I know that no one will be able to answer this tonight, but I still want to know how to do this.
How do you solve 3^(x^2)/3^(3x)=1/9 in Chapter 3 Supplement #3?
How do you solve 3^(x^2)/3^(3x)=1/9 in Chapter 3 Supplement #3?
posted by davidhj at 11:35 PM
1 Comments:
you can cross multiply, then you will get 3^3x=27^(x^2) then you make 27 to 3^3 then you solve the top part of the equation for x neglecting the bottom part( the 3).
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